我有与样本外汇一分钟栏报价表。

id,quote_name,quote_date,quote_time,open_rate,close_rate,high_rate,low_rate "1417","EURUSD","2015-01-01","13:01:00","1.2096","1.2096","1.2097","1.2096" "1418","EURUSD","2015-01-01","13:02:00","1.2097","1.2096","1.2097","1.2096" "1419","EURUSD","2015-01-01","13:04:00","1.2096","1.2098","1.2101","1.2096" "1420","EURUSD","2015-01-01","13:05:00","1.2099","1.2099","1.2099","1.2099"

有可能创建 select 语句将返回 5 分钟间隔报价。我的意思是它应该选择 5 行每个 5 的格拉斯间隔和返回 open_rate 从第一行中，从上次的报价和 min close_rate 和最大的 high_rate 和 low_rate 之间。 这根本是可能的吗？如何做到这一点。

我所知道的是，如何选择最小和最大值两个日期之间。

解决方法 1:

五分钟的时间间隔是有点疼。 一种方法是将转换为秒和除以 300。 然后，获得第一和最后也是棘手。 在这种情况下，建议技巧使用 substring_index() 和 group_concat() :

select quote_date, min(open_time) as open_time, substring_index(group_concat(open_rate order by quote_time), ',', 1) as first_open, substring_index(group_concat(close_rate order by quote_time desc), ',', 1) as last_close, min(high_rate), max(high_rate), min(low_rate), max(low_rate) from quotes group by quote_date, floor(to_seconds(quote_time) / 300);

 

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